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Oracle Database SQL Sample Questions (Q279-Q284):
NEW QUESTION # 279
Examine this SQL statement:
SELECT cust_id, cus_last_name "Last Name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses, any one of which can complete the query successfully.
- A. ORDER BY CUST_NO
- B. ORDER BY 2,cust_id
- C. ORDERBY 2, 1
- D. ORDER BY "Last Name"
- E. ORDER BY "CUST_NO"
Answer: C,D
Explanation:
In SQL, the ORDER BY clause can refer to columns by their alias defined in the SELECT clause or by their positional number in the SELECT list. It's important to understand that after a UNION, the column names in the ORDER BY clause refer to the first SELECT statement's column names and aliases:
* Option A: ORDER BY 2, 1This is correct because it refers to the second and first columns in the first SELECT clause, which correspond to the aliases "Last Name" and cust_id, respectively.
* Option E: ORDER BY "Last Name"This is correct because "Last Name" is a valid alias defined in the first SELECT clause.
The other options fail for the following reasons:
* Option B: "CUST_NO" is not recognized in the ORDER BY clause because it's not an alias used in the first SELECT statement.
* Option C: Incorrect because 2, cust_id mixes positional reference with a column name that doesn't apply to both SELECT statements consistently.
* Option D: ORDER BY CUST_NO fails because CUST_NO is not an alias in the first SELECT clause.
NEW QUESTION # 280
Examine the types and examples of relationships that follow:
Which option indicates correctly matched relationships? (Choose the best answer.)
- A. 1-c, 2-d, 3-a, and 4-b
- B. 1-c, 2-a, 3-b, and 4-d
- C. 1-d, 2-b, 3-a, and 4-c
- D. 1-a, 2-b, 3-c, and 4-d
Answer: D
NEW QUESTION # 281
View the exhibit for the structure of the STUDENTand FACULTYtables.
You need to display the faculty name followed by the number of students handled by the faculty at the base location.
Examine the following two SQL statements:
Statement 1
SQL>SELECT faculty_name, COUNT(student_id)
FROM student JOIN faculty
USING (faculty_id, location_id)
GROUP BY faculty_name;
Statement 2
SQL>SELECT faculty_name, COUNT(student_id)
FROM student NATURAL JOIN faculty
GROUP BY faculty_name;
Which statement is true regarding the outcome?
- A. Both statements 1 and 2 execute successfully and give the same required result.
- B. Only statement 1 executes successfully and gives the required result.
- C. Both statements 1 and 2 execute successfully and give different results.
- D. Only statement 2 executes successfully and gives the required result.
Answer: B
NEW QUESTION # 282
View the Exhibit and examine the structure of the ORDER_ITEMS table. (Choose the best answer.)
You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?
- A. SELECT order_idFROM order_itemsWHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)FROM order_items) GROUP BY order_id);
- B. SELECT order_idFROM order_itemsWHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)FROM order_itemsGROUP BY order_id)
- C. SELECT order_idFROM order_itemsWHERE(unit_price*quantity)
MAX(unit_price*quantity)GROUP BY order_id); - D. SELECT order_idFROM order_itemsGROUP BY order_idHAVING SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity))FROM order_items GROUP BY order_id);
Answer: D
NEW QUESTION # 283
You have been asked to create a table for a banking application.
One of the columns must meet three requirements:
1: Be stored in a format supporting date arithmetic without using conversion functions
2: Store a loan period of up to 10 years
3: Be used for calculating interest for the number of days the loan remains unpaid Which data type should you use?
- A. TIMESTAMP
- B. INTERVAL YEAR TO MONTH
- C. TIMESTAMP WITH TIMEZONE
- D. INTERVAL DAY TO SECOND
- E. TIMESTAMP WITH LOCAL TIMEZONE
Answer: D
Explanation:
The requirements specify that the data type must support date arithmetic, store a specific period (up to 10 years in terms of days), and be used for day-level calculations. The appropriate data type is:
* A: Incorrect. TIMESTAMP WITH TIMEZONE stores date and time with time zone information, which is not specifically needed for arithmetic or interval storage.
* B: Incorrect. TIMESTAMP stores date and time without considering time zone or providing interval arithmetic functionality.
* C: Incorrect. TIMESTAMP WITH LOCAL TIMEZONE adjusts the time zone but does not inherently support interval arithmetic or storage.
* D: Incorrect. INTERVAL YEAR TO MONTH is used for storing periods in terms of years and months, not suitable for daily calculations.
* E: Correct. INTERVAL DAY TO SECOND allows storage of periods in terms of days, hours, minutes, and seconds, meeting all the given requirements for precision and functionality in date arithmetic related to daily calculations.
NEW QUESTION # 284
......
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